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SSC Sample Paper Mock Test-9 SSC CGL Tear-II Paper-1

  • question_answer
    If\[{{x}^{5}}-9{{x}^{2}}+12x-14\]is divisible by \[(x-3),\]what is the remainder?

    A) 0

    B)  1

    C)  56       

    D)  184

    Correct Answer: D

    Solution :

    On putting \[x=3\]in \[{{x}^{5}}-9{{x}^{2}}+12x-14,\]we get Remainder \[={{(3)}^{5}}-9\,\,{{(3)}^{2}}+12\times 3-14\] \[=243-81+36-14=184\]


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