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NEET Sample Paper NEET Sample Test Paper-10

  • question_answer
    A simple harmonic motion has an amplitude A and time period T. The time required by it to travel from \[X-A\] to \[X=A/2\] is:

    A)  \[T/6\]                        

    B)  \[T/4\]

    C)  \[T/3\]                        

    D)  \[T/2\]

    Correct Answer: A

    Solution :

    Time required to travel from \[X=A\] to \[X=0\]is \[T/4\]and time required to travel from \[X=A/2\]to \[X=0\]is equal to the time required to travel from \[X=0\]to \[X=A/2\]which is equal to, \[Y=A\,\,\sin (2\pi /T)t\] \[A/2=A\,\sin \,\,(2\pi /T)t\] \[\sin \,(\pi /6)=\sin \,\,(2\pi /T)t\]                 \[t=T/12\] Time required to travel from \[X=A\] to \[X=A/2\]will be \[T/4-T/12=T/6\].


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