A) \[\frac{27}{32}\]
B) \[\frac{32}{27}\]
C) \[\frac{4}{9}\]
D) \[\frac{9}{4}\]
Correct Answer: A
Solution :
\[\frac{1}{{{\lambda }_{3-1}}}=R\,\,\left[ \frac{1}{{{(1)}^{2}}}-\frac{1}{{{(3)}^{2}}} \right]=\frac{8R}{9}\] and \[\frac{1}{{{\lambda }_{2-1}}}=R\,\,\left[ \frac{1}{{{(1)}^{2}}}-\frac{1}{{{(2)}^{2}}} \right]=\frac{3R}{4}\] \[\Rightarrow \] \[\frac{{{\lambda }_{3-1}}}{{{\lambda }_{2-1}}}=\frac{27}{32}\]You need to login to perform this action.
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