A) \[13.6\]
B) \[3.4\]
C) \[17.0\]
D) \[10.2\]
Correct Answer: D
Solution :
\[\Delta E=13.6{{z}^{2}}\,\,\left( \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right)\] \[=13.6\times {{(1)}^{2}}\left( \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right)\] \[=13.6\,\,\left( 1-\frac{1}{4} \right)\] \[=13.6\,\,\times \frac{3}{4}=10.2\,\,eV\]
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