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NEET Sample Paper NEET Sample Test Paper-10

  • question_answer
    The metal ion in complex A has EAN identical to the atomic number of krypton. A is: (Atomic number of \[Cr=24,\text{ }Fe=26\] \[Pd=46\])

    A)  \[[Pd{{(N{{H}_{3}})}_{6}}]C{{l}_{4}}\]           

    B)  \[[Cr{{(N{{H}_{3}})}_{5}}Cl]S{{O}_{4}}\]

    C)  \[[Ag{{(N{{H}_{3}})}_{2}}]Cl\]     

    D)  \[[Cr{{(N{{H}_{3}})}_{4}}C{{l}_{2}}]Cl\]

    Correct Answer: C

    Solution :

    \[EAN=Z-(ON)+2(CN)\] where   ON = Oxidation number CN = Co-ordination number Z = atomic number                 \[{{[Fe{{(CN)}_{6}}]}^{4-}}\]                                 EAN = \[26-(2)+2(6)\]                                 \[=26-2+12=36\]


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