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NEET Sample Paper NEET Sample Test Paper-10

  • question_answer
    \[KMn{{O}_{4}}\] (molecular weight = 158) oxidizes oxalic acid in acid medium to \[C{{O}_{2}}\] and water as follows: \[5{{C}_{2}}O_{4}^{2-}+2MnO_{4}^{-}+16{{H}^{+}}\xrightarrow{{}}10C{{O}_{2}}+2M{{n}^{2+}}+8{{H}_{2}}O\]. What is the equivalent weight of \[KMn{{O}_{4}}\]?

    A)  \[158\]                        

    B)  \[31.6\]

    C)  \[39.5\]                       

    D)  \[79\]

    Correct Answer: B

    Solution :

    \[5{{C}_{2}}O_{4}^{2-}+\overset{+7}{\mathop{2MnO_{4}^{-}}}\,+16{{H}^{+}}\xrightarrow{{}}10C{{O}_{2}}+\overset{+2}{\mathop{2M{{n}^{2+}}}}\,+8{{H}_{2}}O\]Equivalent weight \[=\frac{Molecular\text{ }weight}{Change\text{ }in\text{ }oxidation\text{ }number}\] \[=\frac{158}{5}=31.6\]


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