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NEET Sample Paper NEET Sample Test Paper-11

  • question_answer
    Radius of orbit of satellite of earth is R, Its kinetic energy is proportional to

    A)  \[\frac{1}{R}\]                         

    B) \[\frac{1}{\sqrt{R}}\]

    C)  R                                

    D) \[\frac{1}{{{R}^{3/2}}}\]

    Correct Answer: A

    Solution :

     We define kinetic energy of orbiting satellite\[,\]\[KE=\frac{GMm}{2R}\]. Hence \[KE\propto \frac{1}{R}\]


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