A) \[\frac{{{Q}^{2}}}{2{{V}^{2}}}\]
B) \[\frac{1}{2}{{\varepsilon }_{0}}\frac{{{V}^{2}}}{{{d}^{2}}}\]
C) \[\frac{1}{2}\frac{{{V}^{2}}}{{{\varepsilon }_{0}}{{d}^{2}}}\]
D) \[\frac{1}{2}{{\varepsilon }_{0}}\frac{{{V}^{2}}}{d}\]
Correct Answer: B
Solution :
Energy stored per unit volume \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}=\frac{1}{2}{{\varepsilon }_{0}}{{\left( \frac{V}{d} \right)}^{2}}=\frac{1}{2}{{\varepsilon }_{0}}\frac{{{V}^{2}}}{{{d}^{2}}}\] \[\left( \because \,E=\frac{V}{d} \right)\]
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