A) 0.40 g
B) 0.50 g
C) 0.67 g
D) 0.27 g
Correct Answer: D
Solution :
Apply first law of electrolysis during deposition of charge on an electrode through electrolysis. If\[m\]is the mass of a substance deposited or liberated at an electrode during electrolysis, when a charge q passes through electrolyte, then according to Faraday's first law of electrolysis, \[m\propto q\] or \[m=zq\] where z is a constant of proportionality and is called electrochemical equivalent (ECE) of the substance. If an electric current/flows through the electrolyte, then q=It M= zit Here, \[i=1.5\,A,t=10\,\min =10\times 60\,s\] \[z=30\times {{10}^{-5}}\,g{{C}^{-1}}\] Hence, mass of copper deposited on the electrode \[m=30\times {{10}^{-5}}\times 1.5\times 10\times 60\] \[27\times {{10}^{-2}}=0.27g\]
You need to login to perform this action.
You will be redirected in
3 sec
