A) 5kV
B) 50 kV
C) 5 V
D) 50 V
Correct Answer: B
Solution :
By using \[\frac{1}{2}m{{v}^{2}}=QV\] Given,\[m=2g=2\times {{10}^{-3}}kg,v=10\,m/s,\] \[q=2\mu C=2\times {{\,}^{{{10}^{-6}}}}C\] Substituting the values in relation for V, we obtain \[V=\frac{2\times {{10}^{-3}}\times {{(10)}^{2}}}{2\times 2\times {{10}^{-6}}}\] \[=50\times {{10}^{3}}V=50\,kV\]You need to login to perform this action.
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