NEET Sample Paper NEET Sample Test Paper-12

  • question_answer
    A round disc of moment of inertia\[{{I}_{2}}\]about its axis perpendicular to its plane and passing through its centre is placed over another disc of moment of inertia \[{{I}_{1}}\] rotating with an angular velocity \[\omega \]about the same axis. The final angular velocity of the combination of discs is

    A) \[\frac{{{I}_{2}}\omega }{{{I}_{1}}+{{I}_{2}}}\]

    B) \[\omega \]

    C)  \[\frac{{{I}_{1}}\omega }{{{I}_{1}}+{{I}_{2}}}\]

    D)  \[\frac{({{I}_{1}}+{{I}_{2}})\omega }{{{I}_{1}}}\]

    Correct Answer: C

    Solution :

     The angular momentum of a disc of moment of inertia\[{{I}_{1}}\]and rotating about its axis with angular velocity is \[{{L}_{1}}={{I}_{1}}\omega \] When a round disc of moment of inertia\[{{I}_{2}}\]is placed on first disc, then angular momentum of the combination is \[{{L}_{2}}=({{I}_{1}}+{{I}_{2}})\omega '\] In the absence of any external torque, angular momentum remains conserved, i.e., \[{{L}_{1}}={{L}_{2}}\] \[{{I}_{1}}\omega =({{I}_{1}}+{{I}_{2}})\omega '\] \[\Rightarrow \]\[\omega '=\frac{{{I}_{1}}\omega }{{{I}_{1}}{{I}_{2}}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner