A) Urea
B) Ammonium sulphate
C) Ammonium nitrate
D) Calcium nitrate
Correct Answer: A
Solution :
\[N{{H}_{2}}CON{{H}_{2}};\] % of \[N=\frac{Mass\,of\,N}{Mass\,of\,compound}\times 100\] \[=\frac{28}{60}\times 100=46%\]
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