A) 0.15 m
B) 0.12 m
C) 1.5 m
D) 0.5 m
Correct Answer: A
Solution :
By the law of conservation of energy, i.e., \[\Delta \Kappa +\Delta U=0\] \[\left( 0-\frac{1}{2}m{{v}^{2}} \right)+\left( \frac{1}{2}k{{x}^{2}}-0 \right)=0\] \[\frac{1}{2}m{{v}^{2}}=\frac{1}{2}k{{x}^{2}}\] \[\Rightarrow \]\[{{x}^{2}}=\frac{m{{v}^{2}}}{k}\] \[\Rightarrow \]\[x=\sqrt{\left( \frac{m{{v}^{2}}}{k} \right)}\] \[\Rightarrow \]\[x=\sqrt{\left( \frac{0.5\times 1.5\times 1.5}{50} \right)}\] \[\therefore \] = 0.15 mYou need to login to perform this action.
You will be redirected in
3 sec