A) \[1.568\times {{10}^{3}}\]
B) 15.68
C) \[1.568\times {{10}^{4}}\]
D) \[2.136\times {{10}^{4}}\]
Correct Answer: C
Solution :
Suppose the mol. wt. of enzyme \[=x\] Given 100 g of enzyme wt of Se = 0.5 gm \[\therefore \]In \[x\]g of enzyme wt. of Se \[=\frac{0.5}{1000}\times x\] Hence \[78.4=\frac{0.5\times x}{100}\] \[\therefore \]\[x=15680=1.568\times {{10}^{4}}\]You need to login to perform this action.
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