question_answer

\[[Cr{{({{H}_{2}}O)}_{6}}]C{{l}_{3}}\] (at. no. of Cr = 24) has a magnetic  moment of 3.83 BM. The correct distribution of 3d-electrons in the chromium of the complex:

A) \[3d_{xy}^{1},3d_{yz}^{1},3d_{xz}^{1}\]    

B)  \[3d_{xy}^{1},3d_{yz}^{1},3d_{{{z}^{2}}}^{1}\]

C) \[(3d_{{{x}^{2}}-{{y}^{2}}}^{1}),3d_{{{z}^{2}}}^{1},3d_{xz}^{1}\]    

D) \[3d_{xy}^{1},(3d_{{{x}^{2}}-{{y}^{2}}}^{1}),3d_{yz}^{1}\]

Correct Answer: A

Solution :

\[C{{r}^{3+}}:1{{s}^{2}}2{{p}^{2}}2{{p}^{6}},3{{s}^{2}}s{{p}^{6}}3{{d}^{3}}.\]The \[3d_{xy}^{1},3d_{zx}^{1},3d_{yz}^{1}\]has lower energy. \[C{{r}^{3+}}\]is \[3{{d}^{3}}\]in presence of