A) 800 J
B) 1600 J
C) 3200 J
D) 6400 J
Correct Answer: B
Solution :
Efficiency\[=\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=1-\frac{300}{600}=0.5\] \[\eta =\frac{\text{Work}\,\text{done}}{\text{Heat}\,\text{supplied}}=\frac{W}{Q}\] Therefore, \[\frac{1}{2}=\frac{800}{Q},\,\therefore \,Q=1600\,J\] Hence, the correction option is [b].You need to login to perform this action.
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