A) 280 cm
B) 210 cm
C) 175 cm
D) 180 cm
Correct Answer: D
Solution :
\[{{\lambda }_{o}}=230\,nm\][Thre shold wavelength is given] \[{{K}_{\max }}=\frac{hc}{\lambda }\phi =\frac{hc}{\lambda }-\frac{hc}{{{\lambda }_{o}}}\] \[1.5\,eV=\frac{1242\,eV-nm}{\lambda }-\frac{1242eV-nm}{2.30\,nm}\] \[\Rightarrow \]\[\frac{1242}{\lambda }=1.5+5.4=6.9\,or\,\lambda =180\,nm.\] Hence, the correction option is [d].
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