NEET Sample Paper NEET Sample Test Paper-15

  • question_answer A ray of light is incident on the surface of a glass plate of refractive index \[\sqrt{3}\]at the polarizing angle. The angle of refraction is

    A) \[60{}^\circ \]

    B) \[30{}^\circ \]

    C) \[45{}^\circ \]

    D) \[50{}^\circ \]

    Correct Answer: B

    Solution :

    At the polarizing angle \[{{i}_{p}}.\tan {{i}_{p}}=\mu =\sqrt{3}\] Now, \[\frac{\sin {{i}_{p}}}{\operatorname{sinr}}=\mu =\sqrt{3}\] \[\Rightarrow \]\[\sin r=\frac{\sin {{60}^{o}}}{\sqrt{3}}=\frac{1}{2}\]\[\therefore \]\[r={{30}^{o}}\] Hence, the correction option is [b].

You need to login to perform this action.
You will be redirected in 3 sec spinner