• # question_answer A ray of light is incident on the surface of a glass plate of refractive index $\sqrt{3}$at the polarizing angle. The angle of refraction is A) $60{}^\circ$B) $30{}^\circ$C) $45{}^\circ$D) $50{}^\circ$

At the polarizing angle ${{i}_{p}}.\tan {{i}_{p}}=\mu =\sqrt{3}$ Now, $\frac{\sin {{i}_{p}}}{\operatorname{sinr}}=\mu =\sqrt{3}$ $\Rightarrow$$\sin r=\frac{\sin {{60}^{o}}}{\sqrt{3}}=\frac{1}{2}$$\therefore$$r={{30}^{o}}$ Hence, the correction option is [b].