• # question_answer The empirical formula of a compound is $C{{H}_{2}}O.$Its molecular weight is 180. The molecular formula of that compound is A) ${{C}_{6}}{{H}_{12}}{{O}_{6}}$                    B) ${{C}_{6}}H{{O}_{4}}$C) ${{C}_{3}}{{H}_{6}}{{O}_{3}}$                      D) ${{C}_{5}}{{H}_{10}}{{O}_{5}}$

As number of atoms $=\frac{\text{Molecular}\,\text{weight}}{\text{Empirical}\,\text{formula}\,\text{weight}\,\text{of}\,\text{C}{{\text{H}}_{\text{2}}}\text{O}}$ $=\frac{180}{30}=6$ So molecular formula of compound $=6\times \text{empirical}\,\text{formula}\,=6\times C{{H}_{2}}O$ $={{C}_{6}}{{H}_{12}}{{O}_{6}}$ Hence, the correct option is [a].