• # question_answer A body of mass 4 kg moving with velocity 12 m/s collides with another body of mass 6 kg at rest. If the two bodies stick together after collision, then the loss of kinetic energy of the system is A)  0                                B)  288 JC)  172.8 J                      D)  144 J

Loss in $KE=\frac{{{m}_{1}}{{m}_{2}}}{2({{m}_{1}}+{{m}_{2}})}{{({{u}_{1}}{{u}_{2}})}^{2}}$ $=\frac{4\times 6}{2\times 10}{{(12-10)}^{2}}=172.8\,J$ Hence, the correction option is [c].