NEET Sample Paper NEET Sample Test Paper-15

  • question_answer Pressure versus temperature graph of an ideal gas is as shown in the figure. Density of the gas at point A is \[{{\rho }_{0}}.\]Density at point B will be:

    A)  \[\frac{3}{4{{\rho }_{0}}}\]           

    B)  \[\frac{3}{2{{\rho }_{0}}}\]

    C)  \[\frac{4}{3{{\rho }_{0}}}\]           

    D)  \[2{{\rho }_{0}}\]

    Correct Answer: B

    Solution :

    \[\rho =\frac{PM}{RT}\]or \[\rho \propto \frac{P}{T}\]or \[{{\left( \frac{P}{T} \right)}_{A}}=\frac{{{P}_{0}}}{{{T}_{o}}}\]and \[{{\left( \frac{P}{T} \right)}_{B}}=\frac{3}{2}\frac{{{P}_{0}}}{{{T}_{o}}}\] \[\therefore \]\[{{\left( \frac{P}{T} \right)}_{B}}=\frac{3}{2}{{\left( \frac{P}{T} \right)}_{A}}\Rightarrow {{\rho }_{B}}=\frac{3}{2}{{\rho }_{A}}=\frac{3}{2}{{\rho }_{0}}\] Hence, the correction option is .

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