A) 220 V
B) 140 V
C) 100 V
D) 20 V
Correct Answer: C
Solution :
\[E=\sqrt{V_{R}^{2}+{{({{V}_{C}}-{{V}_{L}})}^{2}}}=\sqrt{{{80}^{2}}+{{(100-40)}^{2}}}\] \[=100\,V\] Hence, the correction option is (c).
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