A) \[2{{K}_{1}}={{K}_{2}}\]
B) \[{{K}_{1}}=2{{K}_{2}}\]
C) \[{{K}_{1}}<{{K}_{2}}/2\]
D) \[{{K}_{1}}>2{{K}_{2}}\]
Correct Answer: C
Solution :
\[\frac{hc}{{{\lambda }_{1}}}-{{\phi }_{0}}={{K}_{1}}\]and \[\frac{hc}{{{\lambda }_{1}}/2}-{{\phi }_{0}}={{K}_{2}}\] \[\Rightarrow \]\[{{K}_{2}}+{{\phi }_{0}}=2({{K}_{1}}+{{\phi }_{0}})\] \[\Rightarrow \]\[{{K}_{2}}+2{{K}_{1}}+{{\phi }_{0}}\] \[\Rightarrow \]\[{{K}_{2}}>2{{K}_{1}}\]\[\therefore \]\[{{K}_{1}}<{{K}_{2}}/2\] Hence, the correction option is (c).You need to login to perform this action.
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