A) \[\frac{3V}{K+2}\]
B) \[3V(K+2)\]
C) \[\frac{K+2}{3V}\]
D) \[\frac{3(K+2)}{V}\]
Correct Answer: A
Solution :
The total quantity of charge on the system remains constant after disconnecting the battery \[q=3CV=(KC+2C)V'\] \[\therefore \] \[V'=\frac{3V}{K+2}\] Hence, the correction option is (a).You need to login to perform this action.
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