A) 2.5 m/s
B) 5 m/s
C) 10 m/s
D) 20 m/s
Correct Answer: C
Solution :
Invoking \[S=ut+\frac{1}{2}a{{t}^{2}}\]in the vertical direction \[-S=-\frac{1}{2}\times 10{{t}^{2}}\Rightarrow t=1\,s\] Along the \[x-\]axis \[10=u\times t\] or, \[u=\frac{10}{t}=\frac{10}{1}=10\,m/s.\] Hence, the correction option is (c).You need to login to perform this action.
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