A) \[~6\text{ }m{{s}^{-2}}\]
B) \[~12\text{ }m{{s}^{-2}}\]
C) \[~~18\text{ }m{{s}^{-2}}\]
D) \[~27\text{ }m{{s}^{-2}}\]
Correct Answer: D
Solution :
In the frame of block M, m is in rest N = ma For not falling, \[mg<{{f}_{L}}\] or \[mg<\mu N\] or \[mg<\mu ma\] or \[mg<\mu ma\] or \[a>\frac{g}{\mu }\] \[\therefore \] \[{{a}_{\min }}=\frac{g}{\mu }=\frac{9.8}{0.363}=27\,m/{{s}^{2}}\] Hence, the correction option is [d].You need to login to perform this action.
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