A) \[\frac{2}{3}mg\,\sin \theta \]
B) \[\frac{3}{2}mg\,\sin \theta \]
C) \[\frac{1}{2}mg\,\sin \theta \]
D) \[2mg\,\sin \theta \]
Correct Answer: C
Solution :
From force diagram in figure [a], \[mg\sin \theta -T=ma.\] (i) In force diagram in the figure [b], T = ma (ii) From Eqs. (i) and (ii), \[a=\frac{g}{2}\sin \theta \] \[\therefore \]\[T=\frac{mg\sin \theta }{2}\] Hence, the correction option is [c].You need to login to perform this action.
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