question_answer

In the following reaction, the product 'R' is \[Ca{{C}_{2}}\xrightarrow{{{H}_{2}}O}P\xrightarrow[\text{Tube}]{\text{Hot}\,\text{iron}}Q\xrightarrow[\text{AlC}{{\text{l}}_{\text{3}}}]{\text{C}{{\text{H}}_{\text{3}}}\text{Cl}}R\]

A)  Toluene

B)  n-propylbenzene

C)  Ethylbenzene

D)  Benzene

Correct Answer: A

Solution :

\[Ca{{C}_{2}}+2{{H}_{2}}O\to \underset{\text{Acetylene}\,\text{(P)}}{\mathop{HC\equiv HC}}\,+\underset{\text{Calcium}\,\text{Carbide}}{\mathop{Ca{{(OH)}_{2}}}}\,\] Hence the product ?R? is toluene. Hence, the correct option is (a).