A) 4
B) 2
C) 3
D) 1
Correct Answer: C
Solution :
Here iodine is liberated from potassium iodide as follows: \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+4{{H}_{2}}S{{O}_{4}}\to \] \[{{K}_{2}}S{{O}_{4}}+C{{r}_{2}}{{(S{{O}_{4}})}_{3}}+4{{H}_{2}}O+3[O]\] \[[2KI+{{H}_{2}}S{{O}_{4}}+[O]\to {{K}_{2}}S{{O}_{4}}+{{I}_{2}}+{{H}_{2}}O]\times 3\] \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}+6KI+7{{H}_{2}}S{{O}_{4}}\to \] \[4{{K}_{2}}S{{O}_{4}}+C{{r}_{2}}{{(S{{O}_{4}})}_{3}}+7{{H}_{2}}O+3{{I}_{2}}\] Hence, the correct option is (c).
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