NEET Sample Paper NEET Sample Test Paper-17

  • question_answer A conducting bar is pulled with a constant speed U on a smooth conducting rail. The region has a steady magnetic field of induction B as shown in the figure. If the speed of the bar is doubled then the rate of heat dissipation will:

    A)  remain constant.

    B)  become quarter of the initial value.

    C)  become four fold.

    D)  get doubled.

    Correct Answer: C

    Solution :

    \[\varepsilon =Blv,\,I=\frac{\varepsilon }{r}=\frac{Blv}{R},P={{I}^{2}}R=\frac{{{B}^{2}}{{l}^{2}}{{v}^{2}}}{R}\] i.e., \[P\propto {{v}^{2}}.\] Hence, the correction option is [c].


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