A) \[\frac{{{F}^{2}}{{t}^{2}}}{m}+6\]
B) \[\frac{{{F}^{2}}{{t}^{2}}}{2m}\]
C) \[\frac{{{F}^{2}}{{t}^{2}}}{3m}\]
D) \[\frac{Ft}{2m}\]
Correct Answer: B
Solution :
\[K.E.=m{{v}^{2}}=\frac{1}{2}.\frac{{{m}^{1}}{{v}^{1}}}{m}=\frac{{{p}^{2}}}{2m}={{\left( \frac{Ft}{2m} \right)}^{2}}=\frac{{{F}^{2}}{{t}^{2}}}{2m}\] [\[\because \]Impulse = change in momentum] Hence, the correction option is [b].
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