A) \[g\tan \,\beta \]
B) \[mg\,\cos \beta \]
C) \[(M+m)\cos ec\beta \]
D) \[(M+m)g\tan \beta \]
Correct Answer: D
Solution :
Different force involved are shown in the figure. Acceleration of system \[a=\frac{P}{(M+m)}\] Force on block of mass\[m=\frac{Pm}{M+m}\] If f is reaction of m on M, then \[f=\frac{Pm}{M+m}\] The mass m will remain stationary if \[f\cos \cos \beta =mg\sin \sin \beta \] \[m=\frac{Pm}{M+m}\cos \cos \beta =mg\sin \sin \beta \] \[P=g(M+m)\frac{\sin \sin \beta }{\cos \cos \beta }\] \[P=(M+m)g\tan \tan \beta \] Hence, the correction option is [d].
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