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NEET Sample Paper NEET Sample Test Paper-18

  • question_answer
       The logarithm of the equilibrium constant of the cell reaction corresponding to the cell \[X(s)|{{X}^{2+}}(aq)||{{Y}^{+}}(aq)|Y(s)\]with standard cell potential,\[E_{cell}^{o}=1.2\,V\] is given by

    A)  40.2                           

    B)  47.2

    C)   12.5                          

    D)  21.5

    Correct Answer: A

    Solution :

    \[{{E}^{o}}=\frac{0.0591}{n}\log {{K}_{eq}}\] So, \[\log \,{{K}_{eq}}=\frac{{{E}^{o}}\times n}{0.0591}=\frac{1.20\times 2}{00591}=40.6.\] Hence, the correct option is [a].


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