NEET Sample Paper NEET Sample Test Paper-18

  • question_answer
    When a force is applied at one end of an elastic wire, it produces a strain £ in the wire.  If Y is the Young's modulus of the material of the wire, the amount of energy stored per unit volume of the wire is given by

    A) \[Y\times e\]                

    B) \[\frac{1}{2}(Y\times \varepsilon )\]

    C) \[Y\times {{\varepsilon }^{2}}\]                  

    D)  \[\frac{1}{2}(Y\times {{\varepsilon }^{2}})\]  

    Correct Answer: D

    Solution :

    Energy stored per unit volume \[=\frac{1}{2}(stress\times strain).\]But stress = Young's modulus \[\times \]strain. Therefore energy stored per unit volume \[=\frac{1}{2}Y{{\varepsilon }^{2}},\] which is choice [d]. Hence, the correction option is [d].


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