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NEET Sample Paper NEET Sample Test Paper-19

  • question_answer
    A gas is compressed at a constant pressure of \[50\text{ }N/{{m}^{2}}\] from volume of 10 m3 to a volume of \[4\text{ }{{m}^{3}}.\] Energy of 100 J is then added to the gas by heating. Its internal energy is

    A)  increased by 400 J

    B)  increased by 200 J

    C)  increased by 100 J

    D)  decreased by 200 J

    Correct Answer: A

    Solution :

    Work done \[=P\Delta V\,\therefore \,dW=50\times (4-10)\]\[=-300\,J\] Now, \[dQ=dU+dW\ \therefore \,dU=100+300=400\,J\] Hence, the correction option is [a].


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