A) \[{{10}^{-7}}\] weber per meter
B) \[4\pi \times {{10}^{-7}}\] weber per meter
C) \[16{{\pi }^{2}}\times {{10}^{-7}}\]weber per meter
D) 0
Correct Answer: A
Solution :
By Amperes Law, we get, \[\vec{B}.\overrightarrow{dl}={{\mu }_{0}}I=4\pi \times {{10}^{-7}}\times \frac{1}{4\pi }={{10}^{-7}}\,w/{{m}^{2}}\] Hence, the correction option is [a].
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