A) \[HP{{O}_{3}}\]
B) \[{{H}_{3}}P{{O}_{4}}\]
C) \[{{H}_{2}}{{P}_{2}}{{O}_{7}}\]
D) \[{{H}_{3}}P{{O}_{3}}\]
Correct Answer: B
Solution :
The oxidation number of central atom in its anhydrate and acid is same. In \[{{P}_{2}}{{O}_{5}},\]let the oxidation number of\[P=x.\] \[2x-10=0\] In \[{{H}_{3}}P{{O}_{4}},\]let the oxidation number of P = y. \[3+y-8=0\] \[y=+\,5\] As oxidation number of P in\[{{P}_{2}}{{O}_{5}}\]and \[{{H}_{3}}P{{O}_{4}}\]is same, So\[{{P}_{2}}{{O}_{5}}\]is an anhydride of \[{{H}_{3}}P{{O}_{4}}.\] Hence, the correct option is [b].
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