A) \[K=\frac{T\Delta {{S}^{o}}-\Delta {{H}^{o}}}{RT}\]
B) \[K=\frac{\Delta {{H}^{o}}-T\Delta {{S}^{o}}}{RT}\]
C) In \[K=\frac{T\Delta {{S}^{o}}-\Delta {{H}^{o}}}{RT}\]
D) In \[K=\frac{\Delta {{H}^{o}}-T\Delta {{S}^{o}}}{RT}\]
Correct Answer: C
Solution :
\[\because \] \[\Delta {{G}^{o}}=-RT\] In K and \[\Delta {{G}^{o}}=\Delta {{H}^{o}}-T.\] \[\Delta {{S}^{o}}\] Hence, RT In \[K=T\] . \[\Delta {{S}^{o}}-\Delta {{H}^{o}}\] or In \[K=\frac{T.\Delta {{S}^{o}}-\Delta {{H}^{o}}}{RT}\]
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