A) 8 seconds
B) 10 seconds
C) 12 seconds
D) 16 seconds
Correct Answer: C
Solution :
\[y=-\frac{2}{3}{{t}^{2}}+16\,t+2.\] Comparing it with \[s=ut+\frac{1}{2}a{{t}^{2}},\]we have \[u=16\,m/s\]and \[\frac{a}{2}=-\frac{2}{3}\]or \[a=-\frac{3}{4}\,m/{{s}^{2}}.\]For a body to come to rest, the final velocity \[v=0.\]Using these values of u, v and a in relation \[v=u+\]at we have 0 =\[0=16-\frac{4}{3}t\]or \[t=12\sec .\]
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