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NEET Sample Paper NEET Sample Test Paper-20

  • question_answer
    The electric potential V (in volt) varies with x (in meter) according the relation\[V=5+4{{x}^{2}}.\] The force experienced by a negative charge  of \[2\times {{10}^{-6}}C\]located at \[x=0.5\,m\]is:

    A) \[2\times {{10}^{-6}}N\]                 

    B) \[4\times {{10}^{-6}}N\]     

    C)      \[6\times {{10}^{-6}}N\]     

    D)      \[8\times {{10}^{-6}}N\]   

    Correct Answer: D

    Solution :

    Electric field \[E=-\frac{dV}{dx}=-\frac{d}{dx}(5+4{{x}^{2}})=-8x\] Force on charge \[(-q)=-qE=8qx\] At \[x=0.5\,m,\] Force\[=8\times 2\times {{10}^{-6}}\times 0.5=8\times {{10}^{-6}}N.\] Hence, the correction option is (d).


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