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NEET Sample Paper NEET Sample Test Paper-20

  • question_answer
    In an ac circuit the potential difference V and current\[I\]are given respectively by \[V=100\sin (100\,t)\]volt and\[I=100\sin (100t+\pi /3)\,mA.\]The power dissipated in the circuit will be

    A) \[~{{10}^{4}}W\]  

    B)                   10 W  

    C)       2.5 W              

    D)       5 W

    Correct Answer: C

    Solution :

    Voltage amplitude \[{{V}_{0}}=100V,\]current amplitude and phase difference between I and V is\[\phi =\frac{\pi }{3}={{60}^{o}}.\]Now power dissipated is given by \[P=\frac{{{V}_{0}}{{I}_{0}}}{2}\cos \Phi \frac{100\times 100\times {{10}^{-3}}}{2}\cos {{60}^{o}}=2.5\,W.\] Hence, the correction option is (c).


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