A) \[1\,s\]
B) \[\frac{1}{\ell n\,2}s\]
C) \[(\ell n\,2)s\]
D) 2 s
Correct Answer: C
Solution :
\[\frac{dN}{dt}=200-\lambda N=200-N\] \[\Rightarrow \]\[\int_{0}^{N}{\frac{dN}{200-N}=\int_{0}^{t}{dt}}\] \[\therefore \]\[t=\ell n\left( \frac{200}{200-N} \right)=\ell n\left( \frac{200}{200-100} \right)=(\ell n2)\sec \] Hence, the correction option is (c).
You need to login to perform this action.
You will be redirected in
3 sec
