A) 1/8
B) 1/4
C) 1/16
D) 1/2
Correct Answer: C
Solution :
\[T=12\,days\,{{t}^{1/2}}=3\,days\] \[n\](number of half-lives)\[=\frac{12}{3}=4\] Amount of substance left\[=\frac{{{N}_{0}}}{{{2}^{n}}}\] \[=\frac{{{N}_{0}}}{{{2}^{4}}}=\frac{{{N}_{10}}}{16}\] So,\[\frac{1}{16}\] of the original amount is the answer. Hence, the correct option is (c).You need to login to perform this action.
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