A) \[C{{H}_{3}}I-66{{\,}^{o}}C,42{{\,}^{o}}C\]
B) \[C{{H}_{3}}F-115{{\,}^{o}}C,78{{\,}^{o}}C\]
C) \[{{C}_{2}}{{H}_{5}}Cl-94{{\,}^{o}}C,3{{\,}^{o}}C\]
D) \[{{C}_{2}}{{H}_{5}}Cl-139{{\,}^{o}}C,12{{\,}^{o}}C\]
Correct Answer: A
Solution :
As \[C{{H}_{3}}I\]has a boiling point of \[42{}^\circ C\] which is above the room temperature so, it is liquid in room temperature and solidifies at around \[66{}^\circ C\]. Hence, the correct option is (a).
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