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NEET Sample Paper NEET Sample Test Paper-20

  • question_answer
    In Young's double slit experiment, the two equally bright slits are coherent, but of phase difference \[\pi /3.\]If maximum intensity on the screen is \[{{I}_{o}},\]the intensity at the point on the screen equidistant from the slits is

    A) \[{{I}_{o}}\]              

    B) \[\frac{{{I}_{o}}}{2}\]                                 

    C) \[\frac{{{I}_{o}}}{4}\]                     

    D)      \[\frac{3{{I}_{o}}}{4}\]  

    Correct Answer: D

    Solution :

    \[I={{I}_{0}}{{\cos }^{2}}\frac{\phi }{2}={{I}_{o}}{{\cos }^{2}}\frac{60}{2}={{I}_{0}}\times {{\left( \frac{\sqrt{3}}{2} \right)}^{2}}=\frac{3{{I}_{0}}}{4}\] Hence, the correction option is (d).


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