question_answer

Ethylene is reacted with \[B{{r}_{2}}/CC{{l}_{4}}\]to form X. When X is reacted with alcoholic KOH. Y is formed. X and Y respectively are:

A) \[BrC{{H}_{2}}-C{{H}_{2}}Br\]and\[{{C}_{2}}{{H}_{2}}\]

B) \[{{C}_{2}}{{H}_{5}}\]and\[{{C}_{6}}{{H}_{6}}\]

C) \[{{C}_{2}}{{H}_{5}}Br\]and\[{{C}_{2}}{{H}_{6}}\]    

D) \[{{C}_{2}}{{H}_{3}}B{{r}_{3}}\]and\[{{C}_{2}}{{H}_{4}}\]

Correct Answer: A

Solution :

Hence, the correct option is (a).