A) \[8\times {{1}^{-3}}\,\text{mol/litre}\]
B) \[2.2\times {{10}^{-5}}\,\text{mol/litre}\]
C) \[4.2\times {{10}^{-4}}\,\text{mil/litre}\]
D) \[1.4\times {{10}^{-8}}\,\text{mol/litre}\]
Correct Answer: A
Solution :
\[HgS{{O}_{4}}\underset{S}{\mathop{H{{g}^{+2}}}}\,+SO_{4}^{-2}\] \[{{K}_{sp}}={{S}^{2}}\] or \[S=\sqrt{{{K}_{sp}}}=\sqrt{6.4\times {{10}^{-5}}}\] \[=8\times {{10}^{-3}}\,\text{mol/lit}\] Hence, the correct option is (a).
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