A) 1 carbon atom less than amide.
B) 1 hydrogen atom more than amide.
C) 1 carbon atom more than amide.
D) 1 hydrogen atom less than amide.
Correct Answer: A
Solution :
\[C{{H}_{3}}CON{{H}_{2}}+B{{r}_{2}}\xrightarrow[-2{{H}_{2}}O]{4KOH}\] \[\underset{(Methyl\,amine)}{\mathop{C{{H}_{2}}N{{H}_{2}}}}\,+2KBr+2{{K}_{2}}C{{O}_{3}}\] Hence, the correct option is (a).
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