A) its velocity is constant
B) its kinetic energy is constant
C) it moves in a circular path
D) both [b] and [c] are correct
Correct Answer: D
Solution :
A force of constant magnitude, which is always perpendicular to the velocity of the particle does no do work. Hence, KE of the particle is constant. A force is perpendicular to the velocity the particle moves in a circular path. Hence, the correction option is [d].You need to login to perform this action.
You will be redirected in
3 sec