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NEET Sample Paper NEET Sample Test Paper-24

  • question_answer
    A ring is made of a wire having a resistance \[{{R}_{0}}=12\,\Omega .\]Find the points A and B, as shown in the figure, at which a current carrying conductor should be connected so that the resistance R of the sub-circuit between these points is equal to \[\frac{8}{3}\Omega .\]

    A)  \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{1}{2}\]

    B)  \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{5}{8}\]

    C)  \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{1}{3}\]

    D)  \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{3}{8}\]

    Correct Answer: A

    Solution :

     \[\left( \frac{A}{\rho {{l}_{1}}}+\frac{A}{\rho {{l}_{2}}} \right)=\frac{3}{8}\]                           (i) \[\frac{\rho ({{l}_{2}}+{{l}_{2}})}{A}=12\]                                          (ii) Solving \[\frac{{{l}_{1}}}{{{l}_{2}}}=\frac{1}{2}\]


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